Way to setup URL of event from header

Hello, anyone
the code (app.py):

from flask import Flask
import sentry_sdk
from sentry_sdk.integrations.flask import FlaskIntegration

sentry_sdk.init(
  dsn=“https://<some_key>@<mydomain.ltd>/32”,
  integrations=[FlaskIntegration()],
  )

app = Flask(name)

@app.route(’/’)
def hello_world():
    return 1/0

Dockerfile:

FROM python:3.7-alpine
RUN pip install flask sentry-sdk sentry-sdk[flask]
COPY app.py /opt/app.py
ENV FLASK_APP=/opt/app.py
CMD flask run --host=0.0.0.0

nginx_vhost.conf:

server {
  location / { return 444; }
  location /some_location/ {
    rewrite ^/some_location/(.+)?$ /$1 break;
    proxy_set_header Host $host;
    proxy_set_header X-Real-IP $remote_addr;
    proxy_set_header X-User-IP $remote_addr;
    proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for;
    proxy_set_header X-Forwarded-Url $host/some_location;
    proxy_pass http://app:5000;
  }
}

docker-compose.yml:

version: “3.9”
services:
    app:
      build: .
    nginx:
      image: nginx:alpine
      ports:
        - 80:80
      volumes:
        - ./nginx_vhost.conf:/etc/nginx/conf.d/default.conf
      depends_on:
        - app

docker-compose up -d…
curl localhost > get 500 (it’s ok)
but on sentry web:


On screenshot url: http://localhost:5000/
is there a way to change the url tag from url “http://localhost:5000/” to value from X-Forwarded-Url? (on example: localhost/some_location/)

Thanks in advance

The only way as I research: modify before_send function